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First law of thermodynamics

Heat absorbed and work done all end up in the internal-energy account.

ΔU = Q + WSenior high physics
Orange: heat Q, blue: work W, green: internal energy change ΔU
t = 0.00 s
Speed
Heat absorbed Q150.0J
Work done on gas W-60.0J
Internal energy change ΔU90.0J
Final temperature372K

Energy vs. time

1730.0-1730.01.32.53.85.0E (J)t (s)● Q● W● ΔU

At every moment, ΔU = Q + W.

Think about it

Absorbing the same 150 J of heat, does the temperature rise more at constant volume or at constant pressure?

Model assumptions0.1 mol of monatomic ideal gas, initially 300 K, 1 L · Processes are slow (quasi-static) · For isochoric, isobaric and isothermal processes E is the heat absorbed; for adiabatic, E is the work done on the gas; negative values mean heat released or work done by the gas

Data log

Set the parameters and click “Record data”. Record several rows with different parameters to plot their relationship and fit a straight line; pause and record at different times to study how a reading changes with time.

How to use the lab

  1. Choose an experimentBrowse the catalog on the left by level or topic, or search for a concept.
  2. Change a parameterDrag a slider or type a value in range. The experiment restarts from its initial state right away.
  3. Slow down and observePause, change the speed, drag to look from another angle in 3D, and use the readings and graph to understand what changes.
  4. Test your ideasRead the explanation and the model assumptions, then answer the question under “Think about it”.